Ответы к учебнику по математике за 2 класс 2 часть Рудницкая. Площадь фигуры. Единицы площади. Номер №14

Вычисли.
80 − (30 + 6)
48 + (6 * 7)
56 − (17 * 0)
28 − 19
31 + 49
69 + 31
(90 − 89) * 5
(100 − 99) : 1
(26 + 47) − 47

Ответ

80 − (30 + 6) = 44
48 + (6 * 7) = 90
56 − (17 * 0) = 56
28 − 19 = 9
31 + 49 = 80
69 + 31 = 100
(90 − 89) * 5 = 5
(100 − 99) : 1 = 1
(26 + 47) − 47 = 26
Вычисления:
80 − (30 + 6) = 80 − 36 = 44

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}30\\ 6\end{array}}\\ \begin{array}{r}36\end{array}\end{array}$

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}80\\ 36\end{array}}\\ \begin{array}{r}44\end{array}\end{array}$
48 + (6 * 7) = 48 + 42 = 90

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}48\\ 42\end{array}}\\ \begin{array}{r}90\end{array}\end{array}$
56 − (17 * 0) = 56 − 0 = 56
28 − 19 = 9

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}28\\ 19\end{array}}\\ \begin{array}{r}9\end{array}\end{array}$
31 + 49 = 80

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}31\\ 49\end{array}}\\ \begin{array}{r}80\end{array}\end{array}$
69 + 31 = 100

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}69\\ 31\end{array}}\\ \begin{array}{r}100\end{array}\end{array}$
(90 − 89) * 5 = 1 * 5 = 5

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}90\\ 89\end{array}}\\ \begin{array}{r}1\end{array}\end{array}$
(100 − 99) : 1 = 1 : 1 = 1

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}100\\ 99\end{array}}\\ \begin{array}{r}1\end{array}\end{array}$
(26 + 47) − 47 = 73 − 47 = 26

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}26\\ 47\end{array}}\\ \begin{array}{r}73\end{array}\end{array}$

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}73\\ 47\end{array}}\\ \begin{array}{r}26\end{array}\end{array}$